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34 posters
Chat Thread
SBSP-
- Posts : 50010
- Post n°782
Re: Chat Thread
http://www.urbandictionary.com/define.php?term=porrakyro7 wrote:What does Porra mean?
SBSP-
- Posts : 50010
- Post n°788
Re: Chat Thread
kyro7 wrote:
I'M BUSSIN.
No it isn't.IIBentII39 wrote:This forum is going down the shitter
Cadbury-
- Posts : 23487
Age : 31
Location : Blackpool
Supports : Not Kenny.
- Post n°790
Re: Chat Thread
IIBentII39 wrote:This forum is going down the shitter
You've only been here a month.
Pippo-
- Formerly known as : Pippo Inzaghi
Posts : 30777
- Post n°791
Re: Chat Thread
kyro7 wrote:
Realistic movie effects.
Very realistic. Blood > Gravity.
Jamie-
- Posts : 24047
Age : 63
Location : Thiago
Supports : That Catalan club
- Post n°793
Re: Chat Thread
Pip wrote:kyro7 wrote:
Realistic movie effects.
Very realistic. Blood > Gravity.
Disagreed.
Danny-
- Posts : 55218
Age : 30
Location : Burscough
- Post n°797
Re: Chat Thread
Oh shit.kyro7 wrote:
Ouch.
Guest- Guest
- Post n°798
Re: Chat Thread
SB, here's what i have so far. Starting with the proof for csc(x)
lim h->0 [csc(x+h) - csc(x)]/h
lim h -> [1/sin(x+h) - 1/sin(x)]/h
lim h->0 [ ( sin(x) - sin(x+h))/(sin(x+h)sin(x))]/h
lim h->0 ( sin(x) - sin(x+h))/h(sin(x+h)sin(x))
I'm not finished yet though, but that's the basic idea. The proof for csc(x) is similar, just sub. cos for sin.
Kyro, I'm going have to ban you for a day based on the precedent set for porn posts.
lim h->0 [csc(x+h) - csc(x)]/h
lim h -> [1/sin(x+h) - 1/sin(x)]/h
lim h->0 [ ( sin(x) - sin(x+h))/(sin(x+h)sin(x))]/h
lim h->0 ( sin(x) - sin(x+h))/h(sin(x+h)sin(x))
I'm not finished yet though, but that's the basic idea. The proof for csc(x) is similar, just sub. cos for sin.
Kyro, I'm going have to ban you for a day based on the precedent set for porn posts.
Last edited by Rei Andros on Fri Aug 26, 2011 11:39 am; edited 1 time in total
SBSP-
- Posts : 50010
- Post n°801
Re: Chat Thread
Ohhh, I didn't think to separate it. I had it as 1/[sin(x+h)-sin(x)]. Thanks.Rei Andros wrote:SB, here's what i have so far. Starting with the proof for csc(x)
lim h->0 [csc(x+h) - csc(x)]/h
lim h -> [1/sin(x+h) - 1/sin(x)]/h
lim h->0 [ ( sin(x) - sin(x+h))/(sin(x+h)sin(x))]/h
lim h->0 ( sin(x) - sin(x+h))/h(sin(x+h)sin(x))
I'm not finished yet though, but that's the basic idea. The proof for csc(x) is similar, just sub. cos for sin.
Kyro, I'm going have to ban you for a day based on the precedent set for porn posts before.
ResurrectionRooney-
- Posts : 17681
Supports : United
- Post n°802
Re: Chat Thread
ahlycotc wrote:
Holy fuck, he must have taken out a few ribs there
Cadbury-
- Posts : 23487
Age : 31
Location : Blackpool
Supports : Not Kenny.
- Post n°805
Re: Chat Thread
Clearly an accident. The guy was apologising.
Pippo-
- Formerly known as : Pippo Inzaghi
Posts : 30777
- Post n°806
Re: Chat Thread
http://www.haxball.com/?roomid=efc2cd942923b9debb1fa3ca1b1fac038e26ee9da32c8c1b17da6a4392afe5bc&pass=1
clues is the password.
clues is the password.
Guest- Guest
- Post n°807
Re: Chat Thread
Rei Andros wrote:SB, here's what i have so far. Starting with the proof for csc(x)
lim h->0 [csc(x+h) - csc(x)]/h
lim h -> [1/sin(x+h) - 1/sin(x)]/h
lim h->0 [ ( sin(x) - sin(x+h))/(sin(x+h)sin(x))]/h
lim h->0 ( sin(x) - sin(x+h))/h(sin(x+h)sin(x))
I'm not finished yet though, but that's the basic idea. The proof for csc(x) is similar, just sub. cos for sin.
Kyro, I'm going have to ban you for a day based on the precedent set for porn posts.
Is this real life?
Jamie-
- Posts : 24047
Age : 63
Location : Thiago
Supports : That Catalan club
- Post n°809
Re: Chat Thread
Pip wrote:Rei, you're a cunt.
Why?